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x^2-150x-0.5=0
a = 1; b = -150; c = -0.5;
Δ = b2-4ac
Δ = -1502-4·1·(-0.5)
Δ = 22502
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-\sqrt{22502}}{2*1}=\frac{150-\sqrt{22502}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+\sqrt{22502}}{2*1}=\frac{150+\sqrt{22502}}{2} $
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